Basic Math Examples

$\frac{6 z}{7 z^{2} - 62 z - 9} - \frac{8 z}{7 z^{2} - 60 z - 27}$

Step 1

Simplify each term.

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Step 1.1

Factor by grouping.

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Step 1.1.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 7 \cdot - 9 = - 63$ and whose sum is $b = - 62$ .

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Step 1.1.1.1

Factor $- 62$ out of $- 62 z$ .

$\frac{6 z}{7 z^{2} - 62 (z) - 9} - \frac{8 z}{7 z^{2} - 60 z - 27}$

Step 1.1.1.2

Rewrite $- 62$ as $1$ plus $- 63$

$\frac{6 z}{7 z^{2} + (1 - 63) z - 9} - \frac{8 z}{7 z^{2} - 60 z - 27}$

Step 1.1.1.3

Apply the distributive property.

$\frac{6 z}{7 z^{2} + 1 z - 63 z - 9} - \frac{8 z}{7 z^{2} - 60 z - 27}$

Step 1.1.1.4

Multiply $z$ by $1$ .

$\frac{6 z}{7 z^{2} + z - 63 z - 9} - \frac{8 z}{7 z^{2} - 60 z - 27}$

Step 1.1.2

Factor out the greatest common factor from each group.

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Step 1.1.2.1

Group the first two terms and the last two terms.

$\frac{6 z}{(7 z^{2} + z) - 63 z - 9} - \frac{8 z}{7 z^{2} - 60 z - 27}$

Step 1.1.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{6 z}{z (7 z + 1) - 9 (7 z + 1)} - \frac{8 z}{7 z^{2} - 60 z - 27}$

Step 1.1.3

Factor the polynomial by factoring out the greatest common factor, $7 z + 1$ .

$\frac{6 z}{(7 z + 1) (z - 9)} - \frac{8 z}{7 z^{2} - 60 z - 27}$

Step 1.2

Factor by grouping.

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Step 1.2.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 7 \cdot - 27 = - 189$ and whose sum is $b = - 60$ .

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Step 1.2.1.1

Factor $- 60$ out of $- 60 z$ .

$\frac{6 z}{(7 z + 1) (z - 9)} - \frac{8 z}{7 z^{2} - 60 (z) - 27}$

Step 1.2.1.2

Rewrite $- 60$ as $3$ plus $- 63$

$\frac{6 z}{(7 z + 1) (z - 9)} - \frac{8 z}{7 z^{2} + (3 - 63) z - 27}$

Step 1.2.1.3

Apply the distributive property.

$\frac{6 z}{(7 z + 1) (z - 9)} - \frac{8 z}{7 z^{2} + 3 z - 63 z - 27}$

Step 1.2.2

Factor out the greatest common factor from each group.

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Step 1.2.2.1

Group the first two terms and the last two terms.

$\frac{6 z}{(7 z + 1) (z - 9)} - \frac{8 z}{(7 z^{2} + 3 z) - 63 z - 27}$

Step 1.2.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{6 z}{(7 z + 1) (z - 9)} - \frac{8 z}{z (7 z + 3) - 9 (7 z + 3)}$

Step 1.2.3

Factor the polynomial by factoring out the greatest common factor, $7 z + 3$ .

$\frac{6 z}{(7 z + 1) (z - 9)} - \frac{8 z}{(7 z + 3) (z - 9)}$

Step 2

To write $\frac{6 z}{(7 z + 1) (z - 9)}$ as a fraction with a common denominator, multiply by $\frac{7 z + 3}{7 z + 3}$ .

$\frac{6 z}{(7 z + 1) (z - 9)} \cdot \frac{7 z + 3}{7 z + 3} - \frac{8 z}{(7 z + 3) (z - 9)}$

Step 3

To write $- \frac{8 z}{(7 z + 3) (z - 9)}$ as a fraction with a common denominator, multiply by $\frac{7 z + 1}{7 z + 1}$ .

$\frac{6 z}{(7 z + 1) (z - 9)} \cdot \frac{7 z + 3}{7 z + 3} - \frac{8 z}{(7 z + 3) (z - 9)} \cdot \frac{7 z + 1}{7 z + 1}$

Step 4

Write each expression with a common denominator of $(7 z + 1) (z - 9) (7 z + 3)$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.1

Multiply $\frac{6 z}{(7 z + 1) (z - 9)}$ by $\frac{7 z + 3}{7 z + 3}$ .

$\frac{6 z (7 z + 3)}{(7 z + 1) (z - 9) (7 z + 3)} - \frac{8 z}{(7 z + 3) (z - 9)} \cdot \frac{7 z + 1}{7 z + 1}$

Step 4.2

Multiply $\frac{8 z}{(7 z + 3) (z - 9)}$ by $\frac{7 z + 1}{7 z + 1}$ .

$\frac{6 z (7 z + 3)}{(7 z + 1) (z - 9) (7 z + 3)} - \frac{8 z (7 z + 1)}{(7 z + 3) (z - 9) (7 z + 1)}$

Step 4.3

Reorder the factors of $(7 z + 1) (z - 9) (7 z + 3)$ .

$\frac{6 z (7 z + 3)}{(7 z + 1) (7 z + 3) (z - 9)} - \frac{8 z (7 z + 1)}{(7 z + 3) (z - 9) (7 z + 1)}$

Step 4.4

Reorder the factors of $(7 z + 3) (z - 9) (7 z + 1)$ .

$\frac{6 z (7 z + 3)}{(7 z + 1) (7 z + 3) (z - 9)} - \frac{8 z (7 z + 1)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 5

Combine the numerators over the common denominator.

$\frac{6 z (7 z + 3) - 8 z (7 z + 1)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6

Simplify the numerator.

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Step 6.1

Factor $2 z$ out of $6 z (7 z + 3) - 8 z (7 z + 1)$ .

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Step 6.1.1

Factor $2 z$ out of $6 z (7 z + 3)$ .

$\frac{2 z (3 (7 z + 3)) - 8 z (7 z + 1)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.1.2

Factor $2 z$ out of $- 8 z (7 z + 1)$ .

$\frac{2 z (3 (7 z + 3)) + 2 z (- 4 (7 z + 1))}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.1.3

Factor $2 z$ out of $2 z (3 (7 z + 3)) + 2 z (- 4 (7 z + 1))$ .

$\frac{2 z (3 (7 z + 3) - 4 (7 z + 1))}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.2

Apply the distributive property.

$\frac{2 z (3 (7 z) + 3 \cdot 3 - 4 (7 z + 1))}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.3

Multiply $7$ by $3$ .

$\frac{2 z (21 z + 3 \cdot 3 - 4 (7 z + 1))}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.4

Multiply $3$ by $3$ .

$\frac{2 z (21 z + 9 - 4 (7 z + 1))}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.5

Apply the distributive property.

$\frac{2 z (21 z + 9 - 4 (7 z) - 4 \cdot 1)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.6

Multiply $7$ by $- 4$ .

$\frac{2 z (21 z + 9 - 28 z - 4 \cdot 1)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.7

Multiply $- 4$ by $1$ .

$\frac{2 z (21 z + 9 - 28 z - 4)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.8

Subtract $28 z$ from $21 z$ .

$\frac{2 z (- 7 z + 9 - 4)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 6.9

Subtract $4$ from $9$ .

$\frac{2 z (- 7 z + 5)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 7

Simplify with factoring out.

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Step 7.1

Factor $- 1$ out of $- 7 z$ .

$\frac{2 z (- (7 z) + 5)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 7.2

Rewrite $5$ as $- 1 (- 5)$ .

$\frac{2 z (- (7 z) - 1 (- 5))}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 7.3

Factor $- 1$ out of $- (7 z) - 1 (- 5)$ .

$\frac{2 z (- (7 z - 5))}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 7.4

Simplify the expression.

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Step 7.4.1

Rewrite $- (7 z - 5)$ as $- 1 (7 z - 5)$ .

$\frac{2 z (- 1 (7 z - 5))}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 7.4.2

Move the negative in front of the fraction.

$- \frac{(2 z) (7 z - 5)}{(7 z + 1) (7 z + 3) (z - 9)}$

Step 7.4.3

Reorder factors in $- \frac{(2 z) (7 z - 5)}{(7 z + 1) (7 z + 3) (z - 9)}$ .

$- \frac{2 z (7 z - 5)}{(7 z + 1) (7 z + 3) (z - 9)}$